Torque on a magnetic dipole or a bar magnet in an uniform magnetic field
1) Consider a bar magnet of length 2l is placed in a magnetic field
of strength B.
2) Suppose the magnet is making
3) if m = strength
of the pole of the magnet, then
a)
magnetic force acting on the north
pole is
F1 = mB (along
the B direction, repulsive)
b)
magnetic force acting on the north
pole is
F2 = mB (opposite
to the B direction, attractive)
Where m = strength
of the pole or magnetic moment of the bar magnet.
4) Now we see that these two forces F1 & F2 are equal and
opposite but they acting at different position of the same object. So, these
forces will develop a torque on the Bar magnet.
5) Now the perpendicular distance between these two
forces is
6) Now the torque acting on the magnet is
t = (Force) × (perpendicular
distance between them)
Since
M = m2l


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