Torque on a magnetic dipole or a bar magnet in an uniform magnetic field

 

1) Consider a bar magnet of length 2l is placed in a magnetic field of strength B.

 



2) Suppose the magnet is making 

angle with the magnetic field.

 


3) if m = strength of the pole of the magnet, then



a)           magnetic force acting on the north pole is

 

     F1  =  mB (along the B direction, repulsive)

 


b)           magnetic force acting on the north pole is

 

     F2  =  mB (opposite to the B direction, attractive)

 


Where  m = strength of the pole or magnetic moment of the bar magnet.



4) Now we see that these two forces F1  &  F2  are equal and opposite but they acting at different position of the same object. So, these forces will develop a torque on the Bar magnet.



5) Now the perpendicular distance between these two forces is





6) Now the torque acting on the magnet is

t   =    (Force)   ×    (perpendicular distance between them)





Since

M  =  m2l