Parallel plate Capacitor
1) Suppose there is a capacitor of parallel plates X & Y and they are
separated by a distance d.
2) Suppose the two plates are separated by air insulating medium
Which have dielectric constant e0
of the medium.
3) Now suppose the plate X of the capacitor is charged +Q
with amount of charge.
4) Then same -Q
amount of the charge will induce to the other plate Y.
5) If each plate has area A. Then surface charge density.
6) Region I: in region I
the electric field is
7) Region III: in region III the electric field is
8) Region II: in region II the electric field is
9) Region II: in region II the potential V
is
V = E × d
From 2.41
we know the value of σ,
putting the value of
10) By definition of capacitor capacitance C
on putting the value of V on this equation we get
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